Python String isalpha() Method
Python String isalpha() method is a built-in method used for string handling. The isalpha() methods returns “True” if all characters in the string are alphabets, Otherwise, It returns “False”. This function is used to check if the argument includes only alphabet characters (mentioned below).
ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz
Syntax:
string.isalpha()
Parameters:
isalpha() does not take any parameters
Returns:
- True: If all characters in the string are alphabet.
- False: If the string contains 1 or more non-alphabets.
Errors and Exceptions:
- It contains no arguments, therefore an error occurs if a parameter is passed
- Both uppercase and lowercase alphabets return “True”
- Space is not considered to be the alphabet, therefore it returns “False”
Examples
Input : string = 'Ayush' Output : True Input : string = 'Ayush Saxena' Output : False Input : string = 'Ayush0212' Output : False
Example 1: Working of isalpha()
- Python3
# Python code for implementation of isalpha() # checking for alphabetsstring = 'Ayush'print(string.isalpha()) string = 'Ayush0212'print(string.isalpha()) # checking if space is an alphabetstring = 'Ayush Saxena'print( string.isalpha()) |
Output:
True False False
Example 2: Practical Application
Given a string in python, count number of alphabets in the string and print the alphabets.
Input : string = 'Ayush Saxena'
Output : 11
AyushSaxena
Input : string = 'Ayush0212'
Output : 5
Ayush
Algorithm:
- Initialize a new string and variable counter to 0.
- Traverse the given string character by character upto its length, check if character is an alphabet.
- If it is an alphabet, increment the counter by 1 and add it to a the new string, else traverse to the next character.
- Print the value of the counter and the new string.
- Python3
# Python program to illustrate# counting number of alphabets # using isalpha() # Given stringstring='Ayush Saxena'count=0 # Initialising new stringsnewstring1 =""newstring2 ="" # Iterating the string and checking for alphabets# Incrementing the counter if an alphabet is found# Finally printing the countfor a in string: if (a.isalpha()) == True: count+=1 newstring1+=aprint(count)print(newstring1) # Given stringstring='Ayush0212'count=0for a in string: if (a.isalpha()) == True: count+=1 newstring2+=aprint(count)print(newstring2) |
Output:
11 AyushSaxena 5 Ayush
Last Updated on October 28, 2021 by admin