Python | Replace substring in list of strings
While working with strings, one of the most used application is replacing the part of string with another. Since string in itself is immutable, the knowledge of this utility in itself is quite useful. Here the replacement of a substring in list of string is performed. Let’s discuss certain ways in which this can be performed.
Method #1 : Using list comprehension + replace()
The replace method can be coupled with the list comprehension technique to achieve this particular task. List comprehension performs the task of iterating through the list and replace method replaces the section of substring with another.
# Python3 code to demonstrate# Replace substring in list of strings# using list comprehension + replace() # initializing list test_list = ['4', 'kg', 'butter', 'for', '40', 'bucks'] # printing original list print("The original list : " + str(test_list )) # using list comprehension + replace()# Replace substring in list of stringsres = [sub.replace('4', '1') for sub in test_list] # print resultprint("The list after substring replacement : " + str(res)) |
Output :
The original list : ['4', 'kg', 'butter', 'for', '40', 'bucks'] The list after substring replacement : ['1', 'kg', 'butter', 'for', '10', 'bucks']
Method #2 : Using map() + lambda + replace()
The combination of these functions can also be used to perform this particular task. The map and lambda help to perform the task same as list comprehension and replace method is used to perform the replace functionality. But this method is poor when it comes to performance than method above.
# Python3 code to demonstrate# Replace substring in list of strings# using list comprehension + map() + lambda # initializing list test_list = ['4', 'kg', 'butter', 'for', '40', 'bucks'] # printing original list print("The original list : " + str(test_list )) # using list comprehension + map() + lambda# Replace substring in list of stringsres = list(map(lambda st: str.replace(st, "4", "1"), test_list)) # print resultprint("The list after substring replacement : " + str(res)) |
Output :
The original list : ['4', 'kg', 'butter', 'for', '40', 'bucks'] The list after substring replacement : ['1', 'kg', 'butter', 'for', '10', 'bucks']
Last Updated on November 13, 2021 by admin