Python – pass multiple arguments to map function
The map() function is a built-in function in Python, which applies a given function to each item of iterable (like list, tuple etc) and returns a list of results or map object.
Syntax :
map(funct, iterbl)
Parameters :
funct : The function which is going to execute for each iterable
iterbl : A sequence or collection of iterable objects which is to be mapped
Note :
- You can pass as many iterable as you like to map() function.
- Ensure that function has one parameter for each iterable.
Example :
- Python3
# Python program to show working# of map() function # Return cube of ndef cube(n): return n**3 # Taking list as iteratorevennum = [2,4,6,8]res = map(cube,evennum)print(list(res)) |
Output :
[8, 64, 216, 512]
Passing Multiple Arguments to map() function
We can pass multiple iterable arguments to map() function. For this certain rules must be followed-
- Suppose we pass n iterable to map(), then the given function should have n number of arguments.
- These iterable arguments must be applied on given function in parallel.
- In multiple iterable arguments, when shortest iterable is drained, the map iterator will stop.
- But in case of Python 2, the map iterator will stop when longest sequence is finished.
CODE 1 : Passing two lists and ‘sum’ function to map().
Approach:
- Define a function sum, which returns sum of two numbers.
- Declaring and initializing lst1 and lst2.
- Passing sum function, lst1 and lst2 to map().
- The element at index 0 from both the list will pass on as argument to sum function and their sum will be returned.
- This loop continues till elements of one list get exhausted.
- The result will be stored in result list.
- Python3
# Python program to demonstrate# passing of multiple iterable arguments to map()# using 2 lists # Function which return sum of 2 numbersdef sum(a,b): return a+b # list 1lst1=[2,4,6,8] # list 2lst2=[1,3,5,7,9] result=list(map(sum,lst1,lst2))print(result) |
Output :
[3, 7, 11, 15]
CODE 2 : Passing three lists and ‘Multiply’ function to map().
Approach:
- Define a function Multiply, which returns product of three numbers.
- Declaring and initializing lst1, lst2 and lst3.
- Passing Multiply function, lst1, lst2 and lst3 to map().
- The element at index 0 from all three lists will pass on as argument to Multiply function and their product will be returned.
- This loop continues till elements of one list get exhausted.
- The result will be stored in result list.
- Python3
# Python program to demonstrate# passing of multiple iterable arguments to map()# using 3 lists # Function which return product of 2 numbersdef Multiply(a,b,c): return a*b*c # list 1lst1=[2,4,6,8,10,12,14,16] # list 2lst2=[1,3,5,7,9,11,15] #list 3lst3=[2,3,5,7,11,13,17] result=list(map(Multiply,lst1,lst2,lst3))print(result) |
Output :
[4, 36, 150, 392, 990, 1716, 3570]
CODE 3 : Passing ‘division’ function, one list and one tuple to map().
Approach :
- Defining and initializing list and tuple.
- Defining division function which performs division of two number.
- Passing lst, tup and division function to map().
- The element at index 0 from list and tuple will pass on as argument to division function and their quotient will be returned.
- This loop continues till elements of either list or tuple get exhausted.
- The result will be stored in result list.
- Python3
# Python program to demonstrate# passing of multiple iterable arguments to map()# using list and tuple # Function which perform division of 2 numbersdef division(a,b): return a/b # list lst=[2,4,6,8,10,12,14,16] # tupletup=(2,3,5,7,9,11) result=list(map(division,lst,tup))print(result) |
Output :
[1.0, 1.3333333333333333, 1.2, 1.1428571428571428, 1.1111111111111112, 1.0909090909090908]
Last Updated on March 1, 2022 by admin