Python list | pop()
Python list pop() is an inbuilt function in Python that removes and returns the last value from the List or the given index value.
Syntax:
list_name.pop(index)
Parameter:
- index (optional) – The value at index is popped out and removed. If the index is not given, then the last element is popped out and removed.
Returns: The last value or the given index value from the list.
Exception: When the index is out of range, it returns IndexError.
Example 1: Using pop() Method
# Python3 program for pop() methodlist1 = [ 1, 2, 3, 4, 5, 6 ]# Pops and removes the last element from the listprint(list1.pop())# Print list after removing last elementprint("New List after pop : ", list1, "\n")list2 = [1, 2, 3, ('cat', 'bat'), 4]# Pop last three elementprint(list2.pop())print(list2.pop())print(list2.pop())# Print listprint("New List after pop : ", list2, "\n") |
Output:
6
New List after pop : [1, 2, 3, 4, 5]
4
('cat', 'bat')
3
New List after pop : [1, 2]
Example 2
# Python3 program showing pop() method# and remaining list after each poplist1 = [ 1, 2, 3, 4, 5, 6 ]# Pops and removes the last# element from the listprint(list1.pop(), list1)# Pops and removes the 0th index# element from the listprint(list1.pop(0), list1) |
Output:
6 [1, 2, 3, 4, 5] 1 [2, 3, 4, 5]
Example 3: Demonstrating IndexError
- Python3
# Python3 program for error in pop() methodlist1 = [ 1, 2, 3, 4, 5, 6 ]print(list1.pop(8)) |
Output:
Traceback (most recent call last):
File "/home/1875538d94d5aecde6edea47b57a2212.py", line 5, in
print(list1.pop(8))
IndexError: pop index out of range
Example 4: Practical Example
A list of the fruit contains fruit_name and property saying its fruit. Another list consume has two items juice and eat. With the help of pop() and append() we can do something interesting.
- Python3
# Python3 program demonstrating# practical use of list pop()fruit = [['Orange','Fruit'],['Banana','Fruit'], ['Mango', 'Fruit']]consume = ['Juice', 'Eat']possible = []# Iterating item in list fruitfor item in fruit : # Inerating use in list consume for use in consume : item.append(use) possible.append(item[:]) item.pop(-1)print(possible) |
Output:
[['Orange', 'Fruit', 'Juice'], ['Orange', 'Fruit', 'Eat'], ['Banana', 'Fruit', 'Juice'], ['Banana', 'Fruit', 'Eat'], ['Mango', 'Fruit', 'Juice'], ['Mango', 'Fruit', 'Eat']]
Last Updated on October 24, 2021 by admin