hex() function in Python
hex() function is one of the built-in functions in Python3, which is used to convert an integer number into it’s corresponding hexadecimal form.
Syntax :
hex(x) Parameters : x - an integer number (int object) Returns : Returns hexadecimal string.
Errors and Exceptions :
TypeError : Returns TypeError when anything other than
integer type constants are passed as parameters.
Code #1 : Illustrates use of hex() function.
- Python3
# Python3 program to illustrate# hex() functionprint("The hexadecimal form of 23 is " + hex(23)) print("The hexadecimal form of the " "ascii value is 'a' is " + hex(ord('a'))) print("The hexadecimal form of 3.9 is " + float.hex(3.9)) |
Output :
The hexadecimal form of 23 is 0x17 The hexadecimal form of the ascii value os 'a' is 0x61 The hexadecimal form of 3.9 is 0x1.f333333333333p+1
Code #2: Demonstrate TypeError when floating point values are passed as parameter.
- Python3
# hex() accepts only integer vaues as parametersprint("The hexadecimal form of 11.1 is " + hex(11.1))'''# The hexadecimal conversion of floating # point integers can be done using the# function float.hex()print("The hexadecimal form of 11.1 is " + float.hex(11.1))# Output :# The hexadecimal form of 11.1 is 0x1.6333333333333p+3# Similarly, float.hex() throws a TypeError# when integer values are passed in it.''' |
Output :
Traceback (most recent call last):
File "/home/7e1ac7e34362fd690cdb72cf294502e1.py", line 2, in
print("The hexadecimal form of 11.1 is "+hex(11.1))
TypeError: 'float' object cannot be interpreted as an integer
Applications :
hex() is used in all the standard conversions. For example conversion of hexadecimal to decimal, hexadecimal to octal, hexadecimal to binary.
Code #3 :
- Python3
# TypeConversion from decimal with base 10# to hexadecimal form with base 16# Taking input from user# an integer with base 10number = int(input("Enter a number with base 10\n"))# The choices present to the userprint("a. Decimal to Hexadecimal ")print("b. Decimal to Octal")print("c. Decimal to Binary")# taking user inputprint("Enter your choice :- ")choice = input()# Running a variable choice# Hexadecimal form if choice# is set to 'a'if choice is 'a': # lstrip helps remove "0x" from the left # rstrip helps remove "L" from the right, # L represents a long number print("Hexadecimal form of " + str(number) + " is " + hex(number).lstrip("0x").rstrip("L")) if choice is 'b': # Octal representation is done # by adding a prefix "0o" print("Octal form of " + str(number) + " is " + oct(number).lstrip("0o").rstrip("L")) if choice is 'c': # Binary representation is done by # the addition of prefix "0b" print("Binary form of " + str(number) + " is "+bin(number).lstrip("0b").rstrip("L")) |
Output :
input variant a)
Enter a number with base 10 123 a. Decimal to Hexadecimal b. Decimal to Octal c. Decimal to Binary Enter your choice:- a Hexadecimal form of 123 is 7b
input variant b)
Enter a number with base 10 123456789 a. Decimal to Hexadecimal b. Decimal to Octal c. Decimal to Binary Enter your choice:- a Hexadecimal form of 123456789 is 75bcd15
Last Updated on October 26, 2021 by admin