Program to print all the numbers divisible by 3 and 5 for a given number
Given the integer N, the task is to print all the numbers less than N, which are divisible by 3 and 5.
Examples :
Input : 50 Output : 0 15 30 45 Input : 100 Output : 0 15 30 45 60 75 90
Approach : For example, let’s take N = 20 as a limit, then the program should print all numbers less than 20 which are divisible by both 3 and 5. For this divide each number from 0 to N by both 3 and 5 and check their remainder. If remainder is 0 in both cases then simply print that number.
Below is the implementation :
// C++ program to print all the numbers // divisible by 3 and 5 for a given number #include <iostream> using namespace std; // Result function with N void result( int N) { // iterate from 0 to N for ( int num = 0; num < N; num++) { // Short-circuit operator is used if (num % 3 == 0 && num % 5 == 0) cout << num << " " ; } } // Driver code int main() { // input goes here int N = 100; // Calling function result(N); return 0; } // This code is contributed by Manish Shaw // (manishshaw1) |
Output :
0 15 30 45 60 75 90
Last Updated on October 24, 2021 by admin