Check for balanced parentheses in Python
Given an expression string, write a python program to find whether a given string has balanced parentheses or not.
Examples:
Input : {[]{()}} Output : Balanced Input : [{}{}(] Output : Unbalanced
Approach #1 : Using stack
One approach to check balanced parentheses is to use stack. Each time, when an open parentheses is encountered push it in the stack, and when closed parenthesis is encountered, match it with the top of stack and pop it. If stack is empty at the end, return Balanced otherwise, Unbalanced.
# Python3 code to Check for # balanced parentheses in an expression open_list = [ "[" , "{" , "(" ] close_list = [ "]" , "}" , ")" ] # Function to check parentheses def check(myStr): stack = [] for i in myStr: if i in open_list: stack.append(i) elif i in close_list: pos = close_list.index(i) if (( len (stack) > 0 ) and (open_list[pos] = = stack[ len (stack) - 1 ])): stack.pop() else : return "Unbalanced" if len (stack) = = 0 : return "Balanced" else : return "Unbalanced" # Driver code string = "{[]{()}}" print (string, "-" , check(string)) string = "[{}{})(]" print (string, "-" , check(string)) string = "((()" print (string, "-" ,check(string)) |
Output:
{[]{()}} - Balanced [{}{})(] - Unbalanced ((() - Unbalanced
Approach #2 : Using queue
First Map opening parentheses to respective closing parentheses. Iterate through the given expression using ‘i’, if ‘i’ is an open parentheses, append in queue, if ‘i’ is close parentheses, Check whether queue is empty or ‘i’ is the top element of queue, if yes, return “Unbalanced”, otherwise “Balanced”.
# Python3 code to Check for # balanced parentheses in an expression def check(expression): open_tup = tuple ( '({[' ) close_tup = tuple ( ')}]' ) map = dict ( zip (open_tup, close_tup)) queue = [] for i in expression: if i in open_tup: queue.append( map [i]) elif i in close_tup: if not queue or i ! = queue.pop(): return "Unbalanced" if not queue: return "Balanced" else : return "Unbalanced" # Driver code string = "{[]{()}}" print (string, "-" , check(string)) string = "((()" print (string, "-" ,check(string)) |
Output:
{[]{()}} - Balanced ((() - Unbalanced
Approach#3 : Elimination based
In every iteration, the innermost brackets get eliminated (replaced with empty string). If we end up with an empty string, our initial one was balanced; otherwise, not.
# Python3 code to Check for # balanced parentheses in an expression def check(my_string): brackets = [ '()' , '{}' , '[]' ] while any (x in my_string for x in brackets): for br in brackets: my_string = my_string.replace(br, '') return not my_string # Driver code string = "{[]{()}}" print (string, "-" , "Balanced" if check(string) else "Unbalanced" ) |
Output:
{[]{()}} - Balanced
Last Updated on October 28, 2021 by admin